Cs50 Tideman Solution May 2026

for (int i = 0; i < num_voters; i++) for (int j = 0; j < num_candidates; j++) if (strcmp(voters[i].preferences[j], "") != 0) for (int k = 0; k < num_candidates; k++) if (strcmp(candidates[k].name, voters[i].preferences[j]) == 0) candidates[k].votes++;

return false;

// ties are ignored

: Updates a 2D array, preferences[i][j] , which tracks how many voters prefer candidate i over candidate j . 2. Identifying Winners ( add_pairs ) Cs50 Tideman Solution